Step Electric Wheel
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Invacare Pronto M71 Sure Step Electric Wheel Chair, New Batteries |  |
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Step Electric Wheel
Chain Drive Calculation Problems, a question from Mechanical Engineering?
Hi all I'am having a problem in this question. Hopefully there's engineers that's willing to help me out.
A duplex roller chain device is required to drive a paper making machine (class 3) from a 12kW electric motor. The speed of the motor and the machine shafts are 1440 rpm and 600 rpm respectively. The centre distance is not to exceed 400mm. Determine
a) the chain pitch in mm.
b) the chain length in pitches.
c) the actual centre distance.
d) the pitch circle diameter of the pinion and wheel, Hence select the appropriate chain giving its catalogue number.
I know the first step which is to find the drive ratio taking the high speed shaft (1440rpm) divide by low speed shaft(480)
1) 1440/480=2.4
Since they didn't state any teeth so I'am taking it as standard number which is 19
2) 19*2.4=45.6 teeth
n=19 teeth.
N=45.6 teeth.
45.6?! That's not logic! I thought it should be a whole number? Help please?
Because you end up with an odd ratio fgure, multiply it up for a whole number. In this case, 5 works, you end up with a ratio of 12:5.
So the drive sprocket will have tooth no's as multiples of 5, say 25. The driven would then be 60. There is no problem with having even no's of teeth in drive and driven, so long as the no. of rollers is an odd number if there is any chance the number of rollers is evenly divisible by 5. Minor problem.
The rest I cannot help you with. But I think you need to select chain size on pin diameter (strength) primarily, and check it is adequate for transmission of 12kW.
Maximise no's of teeth within constraints of centre distance required and roller pitches.
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Invacare Pronto M71 Sure Step Electric Wheel Chair, New Batteries | |
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US $600.00 | 13d 8h 56m |
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" ONE GUY on ONE WHEEL. "
Electric Motor! Electric Motor! Electric Motor!?
An electric motor can accelerate a Ferris wheel of moment of inertia 24300 kg · m^2 from rest to 10.8 rev/min in 13 s. When the motor is turned off, friction causes the wheel to slow down from 10.8 rev/min to 5.13 rev/min in 8.09 s.
a) Determine the torque generated by the motor to bring the wheel to 10.8 rev/min. Answer in units of N · m.
b) Determine the power needed to maintain the rotational speed at 10.8 rev/min. Answer in units of W.
Step by step calculations!
Thank you for your help!
Wow.
