Seat Elevator Tilt
 |
No items matching your keywords were found.
|
No items matching your keywords were found.
Seat Elevator Tilt
How do astronauts board the space shuttle?
When the astronauts make their way up the elevator to the space shuttle at the launch pad, how do they get inside the cockpit and get seated. Do they have to tilt sideways and try to sit themselves facing up without falling towards the back of the shuttle, or do the seats automatically adjust themselves?
There's an entry door next to the nose, which they have to get to by climbing (well, they probably have an elevator) the launch tower. And yes, they do have to tilt sideways and lie down/sit sideways, and strap themselves it. Sturdiness is more important that comfort, so the seats are as integrated into the cockpit as possible - the seats do not readjust or move at all.
|
No items matching your keywords were found.
|
No items matching your keywords were found.
|
No items matching your keywords were found.
|
|
Elevator $9 Elevator |
|
|
elevator $6.02 elevator |
| We did not find any matches for your request. |
1911 Curtiss Pusher Flight
Oscillations questions?
1. Amtrak's high speed train, the Acela, utilizes tilt of the cars when negotiating curves. The angle of tilt is adjusted so that the main force exerted on the passengers, to provide the centripetal acceleration, is the normal force. The passengers experience less friction force against the seat, thus feeling more comfortable. Consider an Acela train that rounds a curve with a radius of 620 m at a speed of 180 km/h (approximately 113 mi/h).
(a) Calculate the friction force needed on a train passenger of mass 75 kg if the track is not banked and the train does not tilt.
(b) Calculate the friction force on the passenger if the train tilts to its maximum tilt of 8° toward the center of the curve.
2. A 14.7 kg monkey hangs from a cord suspended from the ceiling of an elevator. The cord can withstand a tension of 220 N and breaks as the elevator accelerates. What was the elevator's minimum acceleration? (Assume the positive direction is upward.)
1(a)
F = ma
.. = mv²/r
.. = 75*(180000/3600)²/620
.. = 302.42
Friction force needs to be 302N (correct to 3 figures)
(b) If the normal reaction of the seat is R and the friction force in the direction of the tilted seat is F, then the resultant downward vertical force is
75g - R cos 8° + F sin 8° = 0 since downward acceleration is zero.
The resultant force towards the centre is
F cos 8° + R sin 8° = 302.42
From the first equation,
R = (75g + F sin 8°)/cos 8°,
and replacing R by this expression in the second equation gives
F cos 8° + (75g + F sin 8°) sin 8°/cos 8° = 302.42
Multiply by cos 8°, collect the F terms, and take 75g sin 8° to the right side:
F = 302.42 cos 8° - 75g sin 8°
[using sin² 8° + cos² 8° = 1]
F = 197.18
Friction force is 197N correct to 3 figures.
2. If the tension is F, then
F - 14.7g = 14.7a
The tension reaches 220N when
a = (220 - 14.7g)/14.7
.. = 220/14.7 - g
.. = 5.166
Correct to 3 figures, the minimum acceleration of the elevator (we call them lifts here in Sydney!!) is 5.17 m/s²
